Math::NumSeq::DigitCount -- count of a given digit
use Math::NumSeq::DigitCount; my $seq = Math::NumSeq::DigitCount->new (radix => 10, digit => 9); my ($i, $value) = $seq->next;
The count of how many of a given digit is in
$i when written out in a given radix. The default is to count how many 9s in decimal.
0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, ... starting i=0
For example i=19 has a single "9" so value=1.
digit options can select a different number base or different digit to count. For example to count the 0-bits in binary,
# radix=>2, digit=>0 0, 0, 1, 0, 2, 1, 1, 0, 3, 2, 2, 1, 2, 1, 1, 0, 4, 3, 3, 2, ... starting i=0
i=0 is treated as no digits at all, so it has value=0 for the count of 0-bits, and similarly in other bases counting 0 digits.
digit => -1 gives the highest digit in the radix, ie. radix-1. This is the default, so if
radix is given the count is of its biggest digit.
See "FUNCTIONS" in Math::NumSeq for behaviour common to all sequence classes.
$seq = Math::NumSeq::DigitCount->new (radix => $r, digit => $d)
Create and return a new sequence object.
digitcan be -1 to mean digit radix-1, the highest digit in the radix.
$value = $seq->ith($i)
Return how many of the given
$bool = $seq->pred($value)
Return true if
$valuemight occur as a digit count, which means simply
Copyright 2010, 2011, 2012, 2013 Kevin Ryde
Math-NumSeq is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 3, or (at your option) any later version.
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