Math::NumSeq::JugglerSteps -- steps in the juggler sqrt sequence
use Math::NumSeq::JugglerSteps; my $seq = Math::NumSeq::JugglerSteps->new; my ($i, $value) = $seq->next;
This is the number of steps it takes to reach 1 by the Juggler sqrt sequence,
n -> / floor(n^(1/2)) if n even \ floor(n^(3/2)) if n odd
So sqrt if n even, or sqrt(n^3) if n odd, each rounded downwards. For example i=17 goes 17 -> sqrt(17^3)=70 -> sqrt(70)=8 -> sqrt(8)=2 -> sqrt(2)=1, for a count of 4 steps.
0, 1, 6, 2, 5, 2, 4, 2, 7, 7, 4, 7, 4, 7, 6, 3, 4, 3, 9, 3, ... starting i=1
The intermediate values in the calculation can become quite large and
Math::BigInt is used if necessary. There's some secret experimental caching in a temporary file, for a small speedup.
See "FUNCTIONS" in Math::NumSeq for behaviour common to all sequence classes.
$seq = Math::NumSeq::JugglerSteps->new ()
$seq = Math::NumSeq::JugglerSteps->new (step_type => 'both', juggler_type => '1/2-3/2')
Create and return a new sequence object.
step_typeparameter (a string) selects between
"up" upward steps sqrt(n^3) "down" downward steps sqrt(n) "both" both up and down, which is the default
juggler_typeparameter (a string) selects among variations on the powering
n even n odd "1/2-3/2" sqrt(n) and sqrt(n^3) "2/3-3/2" cbrt(n^2) and sqrt(n^3) "3/4-4/3" n^(3/4) and n^(4/3)
$value = $seq->ith($i)
Return the number of steps to take
$idown to 1.
$bool = $seq->pred($value)
Return true if
$valueoccurs as a step count. This is simply
$value >= 0.
Copyright 2010, 2011, 2012, 2013, 2014, 2016, 2019 Kevin Ryde
Math-NumSeq is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 3, or (at your option) any later version.
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