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NAME

List::Collection - List::Collection

version 0.0.4

SYNOPSIS

use List::Collection;
my @a = qw/1 2 3 4 5 6/;
my @b = qw/4 5 6 7 8 9/;
my @c = qw/5 6 7 8 9 10/;

# get intersection set between two or more List
my @intersect = intersect(\@a, \@b, \@c);  # result is (5,6)

# get union set between two or more List
my @union = union(\@a, \@b, \@c);    # result is (1,2,3,4,5,6,7,8,9,10)

# get substraction between two
my @substract = subtract(\@a, \@b);  # result is (1,2,3)

# get complementation between two or more
my @complement = complement(\@a, \@b);  # result is (1,2,3,7,8,9)

Or in a object-oriented way

use List::Collection;
my @a = qw/1 2 3 4 5 6/;
my @b = qw/4 5 6 7 8 9/;
my \$lc = List::Collection->new();
my @union = \$lc->union(\@a, \@b);
my @intersect = \$lc->intersect(\@a, \@b);

Blablabla

METHODS

new

List::Collection's construction function

intersect

Intersection of multiple Lists, number of parameter could be bigger than two and type is ArrayRef

my @a = qw/1 2 3 4 5 6/;
my @b = qw/4 5 6 7 8 9/;
my @intersect = intersect(\@a, \@b);

union

union set of multiple Lists, number of parameter could be bigger than two and type is ArrayRef

my @a = qw/1 2 3 4 5 6/;
my @b = qw/4 5 6 7 8 9/;
my @union = union(\@a, \@b);

subtract

subtraction(difference set) of two Lists, input parameters' type is ArrayRef

my @a = qw/1 2 3 4 5 6/;
my @b = qw/4 5 6 7 8 9/;
my @subtract = subtract(\@a, \@b);

complement

complement set of multiple Lists, number of parameter could be bigger than two and type is ArrayRef

my @a = qw/1 2 3 4 5 6/;
my @b = qw/4 5 6 7 8 9/;
my @complement = complement(\@a, \@b);

AUTHOR

Yan Xueqing <yanxueqing621@163.com>